Exercices et problèmes

Énoncé

Donnez le degré d'oxydation de chacun des atomes des espèces ci-dessous:

K₂CrO₄	Al(OH)₃	NO₂¯
Pb	IO₃¯	NO₃¯
H₃PO₄	SO₃	NH₄⁺
acétaldéhyde (structure)	Na₂SO₃	SO₃^2-
CaH₂	Rb₂SO₄	SO₄^2-
OF₂	Fe₂S₃	S₄O₆²¯ (structure)
CN¯	Li₂O	S₂O₆^2-
NH₄Br	CCl₄	HCO₃¯
AsO₄^3-	N₂	CH₃OH
Fe³⁺	Fe₃O₄	CH₄
XeO₄	NaN₃	CO₂

Solution

K₂CrO₄	K = +1; Cr = +6; O = -2	Al(OH)₃	Al = +3; O = -2; H = +1	NO₂¯	N = +3; O = -2
Pb	Pb = 0	IO₃¯	I = +5; O = -2	NO₃¯	N = +5; O = -2
H₃PO₄	H = +1; P = +5; O = -2	SO₃	S = +6; O = -2	NH₄⁺	N = -3; H = +1
acétaldéhyde	réponse	Na₂SO₃	Na = +1; S = +4; O = -2	SO₃^2-	S = +4; O = -2
CaH₂	Ca = +2; H = -1	Rb₂SO₄	Rb = +1; S = +6; O = -2	SO₄^2-	S = +6; O = -2
OF₂	O = +2; F = -1	Fe₂S₃	Fe = +3; S = -2	S₄O₆^2-	S = +5, 0, 0, +5; O = -2
CN¯	C = +2; N = -3	Li₂O	Li = +1; O = -2	S₂O₆^2-	S = +5; O = -2
NH₄Br	N = -3; H = +1; Br = -1	CCl₄	C = +4; Cl = -1	HCO₃¯	C = +4; H = +1; O = -2
AsO₄^3-	As = +5; O = -2	N₂	N = 0	CH₃OH	C = -2; H = +1; O = -2
Fe³⁺	Fe = +3	Fe₃O₄	Fe = 3, 3, 2; O = -2 (structure)	CH₄	C = -4; H = +1
XeO₄	Xe = +8; O = -2	NaN₃	Na = +1; N = 0, 0, -1	CO₂	C = +4; O = -2